The Prisoner’s Dilemma [Math for Weirdos]
Monday, October 10th, 2011
Brian and Justin have been captured by prison master Andrew, and are held for questioning. Andrew has enough evidence to prove that Brian and Justin are indeed guilty, but cannot prove the entire extent of their crimes. As he is a good interrogator, Andrew splits Brian and Justin apart (somehow…) to question them individually. Each prisoner now has the opportunity to either “keep their stories straight” (cooperate) or “sell out the other” (defect). Andrew, well aware of this, presents each prisoner with the situation.
Andrew has enough evidence to put both Brian and Justin away for 3 months, but he can play one against the other to get more. If both prisoners cooperate, then he can only “reward” (outcome R) them with 3 months. If one prisoner defects and the other cooperates, then the traitor goes free (outcome T) and the sucker gets a year in prison (outcome S). If both prisoners defect then they are both “punished” (outcome P) with 6 months. In decreasing order, the preferred outcomes (for each prisoner) are then T > R > P > S. So, what would Brian and Justin do? (WWBJD?)
Consider Brian: if Justin cooperates, then Brian can cooperate and receive R or defect and receive T. Conversely, if Justin defects, then Brian can cooperate and receive S, or defect and receive P. Since T > R and P > S, it is to Brian’s advantage to defect regardless of Justin’s behaviour. The same arguments apply for Justin, so it is to both prisoners’ individual advantage to defect. If the prisoners cooperate it is better for them as a whole.
As described, this game consists of a onetime binary choice between two individuals. It can be generalized in many ways. Let’s first play the game more than once: Iterated Prisoner’s Dilemma (best reference ever: http://xkcd.com/696/). Now the actions of each prisoner would certainly influence the strategy of the other.
If the number of iterations of the game is known to both players, or if there is a known limit to the number of iterations then it is to the prisoners’ advantage to defect every time. Why?
We find out AFTER THE JUMP…
(more…)
This week the Nobel Prizes for the year 2011 will be announced. Last week another set of prizes, the Ig Nobels, were awarded to “honor achievements that first make people laugh, and then make them think”. The entire webcast is available
The legend goes…
Remember how weird the notion of infinity was? It gets even better. We know that not all infinities are the same, but let’s show that there is no largest infinity. Before we can do this we need to understand a (very) little set theory.
Seeing as last week all we saw were things that were unknown (and perhaps to celebrate what I hope to be my first proven theorem), why don’t we consider some strategies to establish proof? Of course there are many ways to establish proof, but different strategies work better in certain circumstances. So, let’s look at some ways to prove things.
Prime numbers are just strange, very strange. Let’s look at 2 bizarre properties.
3 people are seated in a circle for some arbitrary, irrelevant purpose. For some reason, they decide to change seats. How many ways can they arrange themselves? It should be easy enough to see that there 6 possible rearrangements; there are 3 choices for the first seat, 2 for the second…
You find yourself on stage contending in one of those old style game shows. The host presents you the challenge: “The game’s simple, all you’ve got to do is choose the right door and the dream prize is yours!” There are 3 doors, one of which guards the grand prize while the other two lead to
Infinity is a weird idea, but just how weird? Would you believe that there are as many even integers as there are integers? How is this possible?










